Solve −2x + 3y = 12, 4x − 4y = −12 by substitution

Worked out line by line the way a teacher would write it.

Answer

Solutionx = 3, y = 6

Step-by-step solution

12 steps
  1. 1 The system, with the equations numbered
    \begin{aligned}3 y - 2 x &= 12 & (1)\\ 4 x - 4 y &= -12 & (2)\end{aligned}
  2. 2 Solve equation (1) for x
    3 y - 2 x = 12
  3. 3 Subtract 3y from both sides
    - 2 x = 12 - 3 y

    Move the constant terms to the right.

  4. 4 Divide both sides by -2
    x = \frac{12 - 3 y}{-2}
  5. 5 Simplify
    x = \frac{3 y}{2} - 6
  6. 6 Substitute x = 3y/2 - 6 into equation (2)
    - 4 y + 4 \left(\frac{3 y}{2} - 6\right) = -12

    Now there is a single equation in y.

  7. 7 Distribute: multiply each term inside the brackets
    - 4 y + 6 y - 24 = -12
  8. 8 Combine like terms
    2 y - 24 = -12
  9. 9 Add 24 to both sides
    2 y = 12

    Move the constant terms to the right.

  10. 10 Divide both sides by 2
    y = \frac{12}{2}
  11. 11 Simplify
    y = 6
  12. 12 Back-substitute y = 6 to find x
    x = \frac{3 \cdot 6}{2} - 6 = 3

Check by substitution

EquationLeft sideRight side
(1)1212✓
(2)−12−12✓
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