Solve 2x + 3y = 12, 4x − y = 10

Worked out line by line the way a teacher would write it.

Answer

Solutionx = 3, y = 2

Step-by-step solution

11 steps
  1. 1 The system, with the equations numbered
    \begin{aligned}2 x + 3 y &= 12 & (1)\\ 4 x - y &= 10 & (2)\end{aligned}
  2. 2 Solve equation (2) for y
    4 x - y = 10
  3. 3 Subtract 4x from both sides
    - y = 10 - 4 x

    Move the constant terms to the right.

  4. 4 Multiply both sides by −1
    y = 4 x - 10
  5. 5 Substitute y = 4x - 10 into equation (1)
    2 x + 3 \left(4 x - 10\right) = 12

    Now there is a single equation in x.

  6. 6 Distribute: multiply each term inside the brackets
    2 x + 12 x - 30 = 12
  7. 7 Combine like terms
    14 x - 30 = 12
  8. 8 Add 30 to both sides
    14 x = 42

    Move the constant terms to the right.

  9. 9 Divide both sides by 14
    x = \frac{42}{14}
  10. 10 Simplify
    x = 3
  11. 11 Back-substitute x = 3 to find y
    y = 4 \cdot 3 - 10 = 2

Check by substitution

EquationLeft sideRight side
(1)1212✓
(2)1010✓
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