Solve x² + 2x + 5 = 0
Quadratic equation, worked out line by line the way a teacher would write it.
Answer
| Solution | no real solution |
Step-by-step solution
6 steps-
1 Givenx^{2} + 2 x + 5 = 0
Solve for x.
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2 This is a quadratic in standard form ax² + bx + c = 0
Every quadratic equation can be arranged as ax² + bx + c = 0. Reading off a = 1, b = 2 and c = 5, signs included, shows which method fits: factoring, taking a square root or the quadratic formula.
a = 1,\quad b = 2,\quad c = 5 -
3 Apply the quadratic formula
The quadratic formula solves any equation ax² + bx + c = 0. It comes from completing the square on the general equation, so it always works, even when the trinomial does not factor.
x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} -
4 Substitute a, b and cx = \frac{-2 \pm \sqrt{2^{2} - 4 \cdot 1 \cdot 5}}{2 \cdot 1}
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5 Compute the discriminant D = b² − 4ac
D = b² − 4ac is the part under the square root in the formula. If it is positive there are two real solutions, if it is 0 there is one, and if it is negative its square root is not a real number, so there is no real solution.
D = -16Negative discriminant: no real solutions (two complex ones).
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6 Complex solutions (not real)x = 2 i - 1\quad \text{or} \quad x = -1 - 2 i
Change a number or try your own problem: the solver works it out the same way, with a graph and hint mode.