Solve tan(x) = √(3) in degrees
Trigonometric equation, worked out line by line the way a teacher would write it.
Answer
| General solution | x = 60° + 180°·n (n any integer) |
Step-by-step solution
6 steps-
1 Given\tan{\left(x \right)} = \sqrt{3}
Solve for x. Angles are in degrees.
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2 Reference angle: the acute angle α with tan α = √3
The reference angle α is the acute angle (between 0 and 90°) whose sine, cosine or tangent has this value, ignoring the sign. The other angles with the same value are built from it in the next step.
\alpha = \arctan\left(\sqrt{3}\right) = 60^{\circ} -
3 Tangent is positive in quadrant I and repeats every half turn
Tangent repeats every half turn (180° or π), so one angle per half turn is enough. It is positive in quadrants I and III and negative in quadrants II and IV.
x = 60^{\circ} -
4 General solution (n is any integer)
Sine and cosine repeat every full turn (360° or 2π) and tangent every half turn, so adding any whole number n of periods gives another solution. n can be any integer, positive, negative or 0.
x = 60^{\circ} + 180^{\circ} n,\quad n \in \mathbb{Z} -
5 The solutions in one turn, 0 ≤ x < 360°x = 60^{\circ},\; 240^{\circ}
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6 Check\begin{aligned}x = 60:\quad \sqrt{3} = \sqrt{3}\quad\checkmark\\ x = 240:\quad \sqrt{3} = \sqrt{3}\quad\checkmark\end{aligned}
Substituting each solution back makes both sides equal.
Check by substitution
| x | Left side | Right side | |
|---|---|---|---|
| 60 | √3 | √3 | ✓ |
| 240 | √3 | √3 | ✓ |
Change a number or try your own problem: the solver works it out the same way, with a graph and hint mode.